[chapter 2 part 1]let us c [SOLVED]

[C]ATTEMPT THE FOLLOWING

(a) If cost price and selling price of an item is input through the keyboard, write a program to determine whether the seller has made profit or incurred loss. Also determine how much profit he made or loss he incurred.


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Answer:
void main()
{
float cp,sp,p;
printf("\nInput the cost price and selling price of an item");
scanf("%f%f",&cp,&sp);
p=sp-cp;
if(p>0)
printf("\nSeller has made a profit of %f",p);
else if(p<0) printf("\nSeller has made a loss of %f",p=0-p); else printf("\nSeller has neither profit nor suffer a loss"); }

(b) Any integer is input through the keyboard. Write a program to find out whether it is an odd number or even number.

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Answer:
void main()
{
float b;
int a;
printf("\nInput an Integer");
scanf("%d",&a);
b=a%2;
if(b==0)
printf("\nInteger is an even number");
else
printf("\nInteger is an odd number");
}

(c)Any year is input through the keyboard. Write a program to determine whether the year is a leap year or not.
(Hint: Use the % (modulus) operator)

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Answer:
void main()
{
int year;
printf("\nInput the year");
scanf("%d",&year);

if((year%4==0&&year%100!=0)||year%400==0)

printf("\nThe Year is a leap year");

else
printf("\nThe Year is not a leap year");
}

(d)According to the Gregorian calendar, it was Monday on the date 01/01/1900. If any year is input through the keyboard write a program to find out what is the day on 1st January of this year.

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Answer:
void main()
{
float days;
int year,diff,leap,type;
long int days1;
printf("\nInput the year");
scanf("%d",&year);
year=year-1;
diff=year-1900;

/* The line year=year-1 was written because we are finding the days before
that particular year not that full year as the required date is 01/01/year.

In days... 365 was added because the year 1900 has to be taken into account
as 1900-1904 is not 1904-1900=4years but is 5 years. 1900 is not a leap year.

In days... addition of one was added because the first day of the year
(1st of Jan) has to be accounted for*/

if(diff<100) { leap =diff/4; days=(366.0*leap)+((diff-leap)*365+365+1); days1=days; type=days1%7; } if(diff>=100)
{
leap = (diff/4)-(diff/100)+1+((year-2000)/400);
days=(366.0*leap)+((diff-leap)*365+365+1);
days1=days;
type=days1%7;
}

if(type==0)
printf("Sunday");
if(type==1)
printf("Monday");
if(type==2)
printf("Tuesday");
if(type==3)
printf("Wednesday");
if(type==4)
printf("Thursday");
if(type==5)
printf("Friday");
if(type==6)
printf("Saturday");

printf("\nThe leap is %d\nThe days is %f\nThe type is %d",leap,days,type);
}

(e)A five-digit number is entered through the keyboard. Write a program to obtain the reversed number and to determine whether the original and reversed numbers are equal or not.


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Answer:
void main()
{
float number,a,b,c,d,e,a2,b2,c2,d2,e2,t;
int a1,b1,c1,d1,e1;
printf("\nInput a 5 digit number");
scanf("%f",&number);
a=number/10000;
a1=a;
b=(number-(10000.0*a1))/1000;
b1=b;
c=(number-(10000.0*a1)-(1000*b1))/100;
c1=c;
d=(number-(10000.0*a1)-(1000*b1)-(100*c1))/10;
d1=d;
e=(number-(10000.0*a1)-(1000*b1)-(100*c1)-(10*d1));
e1=e;

a2=e1*10000.0;
b2=d1*1000.0;
c2=c1*100.0;
d2=b1*10.0;
e2=a1*1.0;

t=a2+b2+c2+d2+e2;

printf("\nThe reversed number is %f",t);
if(t!=number)

printf("\nThe original number and reversed number are not equal");
}

(f)If the ages of Ram, Shyam and Ajay are input through the keyboard, write a program to determine the youngest of the three.

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Answer:
void main()
{
int r,s,a,small;
printf("\nInput the ages of Ram,Shyam and Ajay");
scanf("%d%d%d",&r,&s,&a);
small=(r>s?(s>a?a:s):(r>a?a:r));
if(small==r)
printf("\nThe youngest is Ram with age %d",r);
if(small==s)
printf("\nThe youngest is Shyam with age %d",s);
if(small==a)

printf("\nThe youngest is Ajay with age %d",a);

}

(g)Write a program to check whether a triangle is valid or not, when the three angles of the triangle are entered through the keyboard. A triangle is valid if the sum of all the three angles is equal to 180 degrees.

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Answer:
void main()
{
while (1)
{

float a,b,c;
int s;

printf("\nInput the number of sides the figure has");
scanf("%d",&s);

if(s==3)
printf("\nThe figure is 3 sided");
else
{
printf("\nThe figure is not 3 sided");
break;
}

printf("\nInput the three angles of the triangle");
scanf("%f%f%f",&a,&b,&c);
if(a+b+c==180)
printf("\nThe figure is a triangle");
else
printf("\nThe figure is not a triangle");
break;
}
}

(h) Find the absolute value of a number entered through the
keyboard.


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Answer:
int main()
{
int number;
printf("Enter any no to find absolute value:");
scanf("%d",&number);
if(number<0) number=(-1)*number; printf("Absolute value is: %d",number); getch(); return 0; }

(i)Given the length and breadth of a rectangle, write a program to find whether the area of the rectangle is greater than its perimeter. For example, the area of the rectangle with length = 5 and breadth = 4 is greater than its perimeter.

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Answer:
void main()
{
float l,b,a,p;
printf("Input length and breadth of rectangle");
scanf("%f%f",&l,&b);
a=l*b;
p=2.0*l+2.0*b;
(a>p?printf("\nArea is larger than perimeter"):printf("\nArea is smaller than perimeter"));
}

(j)Given three points (x1, y1), (x2, y2) and (x3, y3), write a program to check if all the three points fall on one straight line.

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Answer:
void main()
{
float x1,x2,x3,y1,y2,y3;
printf("\nEnter the three coordinates (x1,y1),(x2,y2),(x3,y3)");
scanf("%f%f%f%f%f%f",&x1,&y1,&x2,&y2,&x3,&y3);
if ((y2-y1)/(x2-x1)==(y3-y2)/(x3-x2))
printf("\nThe three points fall on the same line");
else
printf("\nThe three points are not collinear");
}

(k) Given the coordinates (x, y) of a center of a circle and it’s radius, write a program which will determine whether a point lies inside the circle, on the circle or outside the circle. (Hint: Use sqrt( ) and pow( ) functions)


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Answer:
int main()
{
int x,y;

printf("Enter co-ordinate(x1,y1)to check position: ");
scanf("%d%d",&x,&y);

if(x==0&&y==0)
printf("\nPoint lies on the origin ");
else if(x==0&&y!=0)
printf("\nPoint lies on the y-axis ");
else
printf("\nPoint lies on the x-axis ");

getch();
return 0;
}

(l) Given a point (x, y), write a program to find out if it lies on the x-axis, y-axis or at the origin, viz. (0, 0).


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Answer:
void main()
{
float x,y;
printf("\nInput the(x,y) values");
scanf("%f%f",&x,&y);
if(x==0&&y==0)
printf("\nThe point lies on the origin");
else if(x==0&&y!=0)
printf("\nThe point lies on the y-axis");
else if(x!=0&&y==0)
printf("\nThe point lies on the x-axis");
else
printf("\nThe point does not lie on any axis or origin");
}

[chapter 1]let us c [SOLVED]

[H]write C programs for the following:

(a)Ramesh’s basic salary is input through the keyboard. His dearness allowance is 40% of basic salary, and house rent allowance is 20% of basic salary. Write a program to calculate his gross salary.

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Answer:

main()
{
float bs,gs;
printf("\nInput Basic Salary");
scanf("%f",&bs);
gs=bs*(16.0/10.0);
printf("\nGross Salary is %f",gs);
}

(b)The distance between two cities (in km.) is input through the keyboard. Write a program to convert and print this distance in meters, feet, inches and centimeters.

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Answer :
main()
{
float distance,distancem,distancefeet,distanceinches,distancecm;
printf("\nInput distance in km");
scanf("%f",&distance);
distancem= distance*1000.0;
distancefeet= distancem*3.2808;
distanceinches= (distance*100000.0)/2.54;
distancecm = distance*100000.0;
printf("\n Distance in metres = %fm\n Distance in feet = %fft\n Distance in inches = %finches\n Distance in cm = %fcm",distancem,distancefeet,distanceinches,distancecm);
}

(c) If the marks obtained by a student in five different subjects are input through the keyboard, find out the aggregate marks and percentage marks obtained by the student. Assume that the maximum marks that can be obtained by a student in each subject is 100.

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main()
{
float a,b,c,d,e,t,am,pm;
printf("\nInput the 5 test marks followed by total obtainable marks");
scanf("%f%f%f%f%f%f",&a,&b,&c,&d,&e,&t);
am=(a+b+c+d+e)/5;
pm=(am/t)*100.0;
printf("\nThe aggregate marks is %f\nThe percentage marks is %f",am,pm);
}

(d)Temperature of a city in Fahrenheit degrees is input through the keyboard. Write a program to convert this temperature into Centigrade degrees.

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Answer:
main()
{
float c,f;
printf("\nInput the temperate(Fahrenheit)");
scanf("%f",&f);
c= (f-32)*(100.0/180.0);
printf("\nThe temperature in Celsius is %f",c);
}

(e) The length & breadth of a rectangle and radius of a circle are input through the keyboard. Write a program to calculate the area & perimeter of the rectangle, and the area & circumference of the circle.

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void main()
{
float l,b,r,arear,perimeterr,areac,perimeterc;
printf("\nInput the length and breadth of rectangle and radius of circle respectively");
scanf("%f%f%f",&l,&b,&r);
arear=l*b;
perimeterr=2*l+2*b;
areac=3.141592654*r*r;
perimeterc=2*3.141592654*r;
printf("\nThe area of rectangle is %f\nThe perimeter of rectangle is %f\nThe area of circle is %f\nThe circumference of the circle is %f",arear,perimeterr,areac,perimeterc);

}

(f) Two numbers are input through the keyboard into two locations C and D. Write a program to interchange the contents of C and D.
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void main()
{
float c,d,e,f;
printf("\nInput values of C and D");
scanf("%f%f",&c,&d);
e=c;
f=d;
c=f;
d=e;
printf("\nNow C is %f\nD is %f",c,d);
}

(g) If a five-digit number is input through the keyboard, write a program to calculate the sum of its digits.
(Hint: Use the modulus operator ‘%’)


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Answer:
void main()
{
float number,a,b,c,d,e;
int a1,b1,c1,d1,e1,t;
printf("\nKey in a five digit number");
scanf("%f",&number);

a=number/10000.0;
a1=a/1;

b=(number-(a1*10000.0))/1000;
b1=b/1;

c=(number-(a1*10000.0)-(b1*1000))/100;
c1=c/1;

d=(number-(a1*10000.0)-(b1*1000)-(c1*100))/10;
d1=d/1;

e=(number-(a1*10000.0)-(b1*1000)-(c1*100)-(d1*10))/1;
e1=e/1;

t=a1+b1+c1+d1+e1;
printf("\nThe sum of the five digits is %d",t);

}

(h) If a five-digit number is input through the keyboard, write a program to reverse the number.

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Answer:
void main()
{
float a,b,c,d,e,t,a2,b2,c2,d2,e2,s;
int a1,b1,c1,d1,e1;
printf("\nInput a 5 digit number");
scanf("%f",&t);
a=t/10000.0;
a1=a;
b=(t-(a1*10000.0))/1000;
b1=b;
c=(t-(a1*10000.0)-(b1*1000))/100;
c1=c;
d=(t-(a1*10000.0)-(b1*1000)-(c1*100))/10;
d1=d;
e=t-(a1*10000.0)-(b1*1000)-(c1*100)-(d1*10);
e1=e;

a2=e1*10000.0;
b2=d1*1000.0;
c2=c1*100.0;
d2=b1*10.0;
e2=a1*1.0;

s=a2+b2+c2+d2+e2;

printf("\nThe required result is %f",s);

}

(i) If a four-digit number is input through the keyboard, write a program to obtain the sum of the first and last digit of this number.

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Answer:

void main()
{
float a,d,t;
int a1,d1,t1,u;
printf("\nInput a 4 digit number");
scanf("%f",&t);
a=t/1000.0;
u=t;
a1=a;
d=u%10;
d1=d;

t1=a1+d1;

printf("\nThe Sum f %d",t1);
}

(k) A cashier has currency notes of denominations 10, 50 and 100. If the amount to be withdrawn is input through the keyboard in hundreds, find the total number of currency notes of each denomination the cashier will have to give to the withdrawer.

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Answer:
Note: So if its $900 the input value is 9 and if its $1970 input is 19.7

void main()
{
float t,_10,_50,_100;
int _11,_51,_101;
printf("\nInput notes in hundreds");
scanf("%f",&t);

_100=t/100;
_101=_100;
_50=(t-_101*100.0)/50;
_51=_50;
_10=(t-(_101*100.0+_51*50.0))/10;
_11=_10;
printf("\n_100 is %f\n_101 is %d",_100,_101);
printf("\nThe no of $100 notes is %d\nThe no of $50 notes is %d\nThe no of $10 notes is %d",_101,_51,_11);
}

(l) If the total selling price of 15 items and the total profit earned on them is input through the keyboard, write a program to find the cost price of one item.

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Answer:

void main()
{
float sp,tp,cp,cps;
printf("\nInput the total selling price of 15 itmes and total profit earned respectively");
scanf("%f%f",&sp,&tp);
cps=sp-tp;
printf("\nThe cost price of one item is %f",cp=cps/15.0);

}

(m) If a five-digit number is input through the keyboard, write a program to print a new number by adding one to each of its digits. For example if the number that is input is 12391 then the output should be displayed as 23402.

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void main()
{
float s,t;
int a,b,c,d,e;
printf("\nInput a 5 digit number");
scanf("%f",&t);

a=t/10000.0;
b=(t-(a*10000.0))/1000;
c=(t-(a*10000.0)-(b*1000))/100;
d=(t-(a*10000.0)-(b*1000)-(c*100))/10;
e=(t-(a*10000.0)-(b*1000)-(c*100)-(d*10))/1;

a+=1;
b+=1;
c+=1;
d+=1;
e+=1;

if (a==10)
a=0;
if (b==10)
b=0;
if (c==10)
c=0;
if (d==10)
d=0;
if (e==10)
e=0;

s=(a*10000.0)+(b*1000.0)+(c*100.0)+(d*10.0)+(e);

printf("\nThe required result is %f",s);
}