[C]ATTEMPT THE FOLLOWING
(a) If cost price and selling price of an item is input through the keyboard, write a program to determine whether the seller has made profit or incurred loss. Also determine how much profit he made or loss he incurred.
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Answer:
void main()
{
float cp,sp,p;
printf("\nInput the cost price and selling price of an item");
scanf("%f%f",&cp,&sp);
p=sp-cp;
if(p>0)
printf("\nSeller has made a profit of %f",p);
else if(p<0) printf("\nSeller has made a loss of %f",p=0-p); else printf("\nSeller has neither profit nor suffer a loss"); }
(b) Any integer is input through the keyboard. Write a program to find out whether it is an odd number or even number.
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Answer:
void main()
{
float b;
int a;
printf("\nInput an Integer");
scanf("%d",&a);
b=a%2;
if(b==0)
printf("\nInteger is an even number");
else
printf("\nInteger is an odd number");
}
(c)Any year is input through the keyboard. Write a program to determine whether the year is a leap year or not.
(Hint: Use the % (modulus) operator)
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Answer:
void main()
{
int year;
printf("\nInput the year");
scanf("%d",&year);
if((year%4==0&&year%100!=0)||year%400==0)
printf("\nThe Year is a leap year");
else
printf("\nThe Year is not a leap year");
}
(d)According to the Gregorian calendar, it was Monday on the date 01/01/1900. If any year is input through the keyboard write a program to find out what is the day on 1st January of this year.
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Answer:
void main()
{
float days;
int year,diff,leap,type;
long int days1;
printf("\nInput the year");
scanf("%d",&year);
year=year-1;
diff=year-1900;
/* The line year=year-1 was written because we are finding the days before
that particular year not that full year as the required date is 01/01/year.
In days... 365 was added because the year 1900 has to be taken into account
as 1900-1904 is not 1904-1900=4years but is 5 years. 1900 is not a leap year.
In days... addition of one was added because the first day of the year
(1st of Jan) has to be accounted for*/
if(diff<100) { leap =diff/4; days=(366.0*leap)+((diff-leap)*365+365+1); days1=days; type=days1%7; } if(diff>=100)
{
leap = (diff/4)-(diff/100)+1+((year-2000)/400);
days=(366.0*leap)+((diff-leap)*365+365+1);
days1=days;
type=days1%7;
}
if(type==0)
printf("Sunday");
if(type==1)
printf("Monday");
if(type==2)
printf("Tuesday");
if(type==3)
printf("Wednesday");
if(type==4)
printf("Thursday");
if(type==5)
printf("Friday");
if(type==6)
printf("Saturday");
printf("\nThe leap is %d\nThe days is %f\nThe type is %d",leap,days,type);
}
(e)A five-digit number is entered through the keyboard. Write a program to obtain the reversed number and to determine whether the original and reversed numbers are equal or not.
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Answer:
void main()
{
float number,a,b,c,d,e,a2,b2,c2,d2,e2,t;
int a1,b1,c1,d1,e1;
printf("\nInput a 5 digit number");
scanf("%f",&number);
a=number/10000;
a1=a;
b=(number-(10000.0*a1))/1000;
b1=b;
c=(number-(10000.0*a1)-(1000*b1))/100;
c1=c;
d=(number-(10000.0*a1)-(1000*b1)-(100*c1))/10;
d1=d;
e=(number-(10000.0*a1)-(1000*b1)-(100*c1)-(10*d1));
e1=e;
a2=e1*10000.0;
b2=d1*1000.0;
c2=c1*100.0;
d2=b1*10.0;
e2=a1*1.0;
t=a2+b2+c2+d2+e2;
printf("\nThe reversed number is %f",t);
if(t!=number)
printf("\nThe original number and reversed number are not equal");
}
(f)If the ages of Ram, Shyam and Ajay are input through the keyboard, write a program to determine the youngest of the three.
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Answer:
void main()
{
int r,s,a,small;
printf("\nInput the ages of Ram,Shyam and Ajay");
scanf("%d%d%d",&r,&s,&a);
small=(r>s?(s>a?a:s):(r>a?a:r));
if(small==r)
printf("\nThe youngest is Ram with age %d",r);
if(small==s)
printf("\nThe youngest is Shyam with age %d",s);
if(small==a)
printf("\nThe youngest is Ajay with age %d",a);
}
(g)Write a program to check whether a triangle is valid or not, when the three angles of the triangle are entered through the keyboard. A triangle is valid if the sum of all the three angles is equal to 180 degrees.
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Answer:
void main()
{
while (1)
{
float a,b,c;
int s;
printf("\nInput the number of sides the figure has");
scanf("%d",&s);
if(s==3)
printf("\nThe figure is 3 sided");
else
{
printf("\nThe figure is not 3 sided");
break;
}
printf("\nInput the three angles of the triangle");
scanf("%f%f%f",&a,&b,&c);
if(a+b+c==180)
printf("\nThe figure is a triangle");
else
printf("\nThe figure is not a triangle");
break;
}
}
(h) Find the absolute value of a number entered through the
keyboard.
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Answer:
int main()
{
int number;
printf("Enter any no to find absolute value:");
scanf("%d",&number);
if(number<0) number=(-1)*number; printf("Absolute value is: %d",number); getch(); return 0; }
(i)Given the length and breadth of a rectangle, write a program to find whether the area of the rectangle is greater than its perimeter. For example, the area of the rectangle with length = 5 and breadth = 4 is greater than its perimeter.
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Answer:
void main()
{
float l,b,a,p;
printf("Input length and breadth of rectangle");
scanf("%f%f",&l,&b);
a=l*b;
p=2.0*l+2.0*b;
(a>p?printf("\nArea is larger than perimeter"):printf("\nArea is smaller than perimeter"));
}
(j)Given three points (x1, y1), (x2, y2) and (x3, y3), write a program to check if all the three points fall on one straight line.
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Answer:
void main()
{
float x1,x2,x3,y1,y2,y3;
printf("\nEnter the three coordinates (x1,y1),(x2,y2),(x3,y3)");
scanf("%f%f%f%f%f%f",&x1,&y1,&x2,&y2,&x3,&y3);
if ((y2-y1)/(x2-x1)==(y3-y2)/(x3-x2))
printf("\nThe three points fall on the same line");
else
printf("\nThe three points are not collinear");
}
(k) Given the coordinates (x, y) of a center of a circle and it’s radius, write a program which will determine whether a point lies inside the circle, on the circle or outside the circle. (Hint: Use sqrt( ) and pow( ) functions)
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Answer:
int main()
{
int x,y;
printf("Enter co-ordinate(x1,y1)to check position: ");
scanf("%d%d",&x,&y);
if(x==0&&y==0)
printf("\nPoint lies on the origin ");
else if(x==0&&y!=0)
printf("\nPoint lies on the y-axis ");
else
printf("\nPoint lies on the x-axis ");
getch();
return 0;
}
(l) Given a point (x, y), write a program to find out if it lies on the x-axis, y-axis or at the origin, viz. (0, 0).
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Answer:
void main()
{
float x,y;
printf("\nInput the(x,y) values");
scanf("%f%f",&x,&y);
if(x==0&&y==0)
printf("\nThe point lies on the origin");
else if(x==0&&y!=0)
printf("\nThe point lies on the y-axis");
else if(x!=0&&y==0)
printf("\nThe point lies on the x-axis");
else
printf("\nThe point does not lie on any axis or origin");
}
